Those products are certainly possible through radical chain termination pathways. I would expect them to be very minor so long as there is more than a molar equivalent of Cl2 and the concentration of propane is kept low.

Think about possible termination steps.

Chlorination is relatively non-selective, but bromination is quite selective. See this post. https://www.masterorganicchemistry.com/2013/10/31/selectivity-in-free-radical-reactions-bromine-vs-chlorine/

You would get mixtures of replacement at C2, C3, and C4. There are twice as many hydrogens that would generate 2-chloropentane than would generate 3-chloropentane, so your dominant product would be 2-chloropentane, but you’d get a mixture of 1-chlropentane, 2-chloropentane, and 3-chloropentane.