Comments on: Haloform Reaction

By: Madhav Mittal

Madhav Mittal — Fri, 28 Jun 2024 07:56:56 +0000

If we have ethyl methyl ketone, when we treat with NaOH, we will majorly form the thermodynamic enolate, so how will any haloform reaction take place?

By: James Ashenhurst

James Ashenhurst — Wed, 27 Apr 2022 02:57:33 +0000

In reply to Matthias. Not under these conditions. The carboxylate is already negatively charged, and a second deprotonation will make a di-anion which is very difficult to do. It can be done but requires a very strong base (n-BuLi).

By: Matthias

Matthias — Tue, 26 Apr 2022 21:14:55 +0000

Is it possible to halogenate the other side after the compound is tuned in a carboxylic acid with the same technique?

By: Ayush Sinha

Ayush Sinha — Fri, 10 Sep 2021 04:46:56 +0000

Thanks! I hope for many more visits to this website after my entrance exams. So comprehensive.

By: James Ashenhurst

James Ashenhurst — Thu, 09 Sep 2021 18:02:29 +0000

In reply to Ayush Sinha. Same as the methyl version, except that the leaving group in this case is a carbon attached to two halogens (not 3) , which is then protonated.

By: Ayush Sinha

Ayush Sinha — Thu, 02 Sep 2021 15:12:08 +0000

How does the non methyl ketone haloform reaction work ?