No, not through any kind of Friedel-Crafts reaction.

I have a few doubts about the mechanism that you have drawn out for the double Friedel-Crafts reaction. In the mechanism, the AlCl3 attacks the carbonyl oxygen atom instead of the oxygen atom which is part of the ring, which is different from how AlCl3 doesn’t attack the carbonyl oxygen atom when we are using acyl halides. Is there a reason why the mechanism is different in this case? And also, if we use the same epoxide ring as before, but without the carbonyl oxygen atoms, will the Friedel-Crafts reactions still take place?

Also, as AlCl3 is a catalyst, we should be getting back AlCl3 by the end of the reactions. However, in your mechanism, we are getting [OAlCl3]− instead. So, shouldn’t the oxygen atom still remain on the carbon chain, resulting in the formation of a carboxylic acid just before the cyclization of the carbon chain occurs?

1) I don’t think there is anything magical about FeCl3. Friedel Crafts rearrangements will happen as soon as heat is applied.

2) Hi, yes, I have drawn out the mechanism for this double Friedel-Crafts acylation reaction.https://cdn.masterorganicchemistry.com/wp-content/uploads/2022/08/Supp-1-Mechanism-for-intramolecular-Friedel-Crafts.gif

2)In this question (https://tinyurl.com/bddnkd97) in the reaction from P to Q, I am not sure how AlCl3 attaches to the Epoxide and how the resulting Friedel-Crafts reaction takes place and I was wondering whether you could explain how this mechanism takes place?