Comments on: Aromatic, Non-Aromatic, or Antiaromatic? Some Practice Problems https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/ Thu, 25 Apr 2024 01:40:08 +0000 hourly 1 https://wordpress.org/?v=6.6.2 By: Victoria https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-691922 Thu, 25 Apr 2024 01:40:08 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-691922 THANK YOU!!!! so helpful!!!!

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By: James Ashenhurst https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-634692 Sat, 06 Aug 2022 02:50:43 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-634692 In reply to Sakib.

The molecule does not exist.

However if you look at azulene, it’s possible to push the arrows such that you get a cyclopentadienyl cation and a heptatrienyl anion, each of which are (in theory) anti aromatic. However based on the dipole moment the contribution of this resonance form is zero

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By: Sak https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-600720 Fri, 07 May 2021 07:11:34 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-600720 I found a source saying cyclobutan-1,2,3-trione is aromatic .Is it correct? If yes please explain how?

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By: Sakib https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-599390 Tue, 30 Mar 2021 08:50:21 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-599390 What will be the aromaticity of a compound having both an aromatic and an antiaromatic ring? Eg- phenyl cyclobutadiene

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By: James Ashenhurst https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-598633 Thu, 11 Mar 2021 17:42:09 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-598633 In reply to Hayley.

It’s not conjugated all the way around the ring. If you look at the nitrogen you’ll see that it is sp3 hybridized (attached to four sigma bonds). If it had an empty p orbital that would give it 5 orbitals which violates the octet rule!

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By: James Ashenhurst https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-598631 Thu, 11 Mar 2021 17:25:15 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-598631 In reply to Olly.

Because the ring meets the rules. : – )

The methyl group has no impact on the aromaticity. Aromaticity is determined by the pi-electrons (i.e. the electrons in the double bonds).

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By: Hayley https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-598626 Thu, 11 Mar 2021 14:23:41 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-598626 Hey James,
why is ”Pyrrole Conjugate Acid” not Aromatic? I assume, it has an empty p-orbital. And with this empty p-orbital, it is possible to build a conjugated phi orbital system with the rest existing phi-bonds.

Thanks in advance!

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By: Olly https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-598519 Sun, 07 Mar 2021 22:47:37 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-598519 Is toluene aromatic because its ring meets the rules, or does the methyl substituent not being planar make it non-aromatic?

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By: Ayush https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-593272 Wed, 06 Jan 2021 11:22:01 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-593272 I can’t understand what is aromatic and also not give any example in simple way

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By: James Ashenhurst https://www.masterorganicchemistry.com/2017/03/03/aromatic-antiaromatic-nonaromatic-some-practice-problems/#comment-590224 Mon, 21 Dec 2020 02:55:23 +0000 https://www.masterorganicchemistry.com/?p=10578#comment-590224 In reply to Lowry.

Count the pi electrons and that should tell you!

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